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NMIMS Global Access
School for Continuing Education (NGA-SCE)
Course: Business Statistics
Assignment Marks: 30
Instructions:
·
All
Questions carry equal marks.
·
All
Questions are compulsory
·
All
answers to be explained in not more than 1000 words for question 1 and 2 and
for question 3 in not more than 500 words for each subsection. Use relevant
examples, illustrations as far aspossible.
·
All
answers to be written individually. Discussion and group work is not advisable.
·
Students
are free to refer to any books/reference material/website/internet for
attempting theirassignments, but are not allowed to copy the matter as it is
from the source of reference.
·
Students
should write the assignment in their own words. Copying of assignments from
otherstudents is not allowed.
·
Students
should follow the following parameter for answering the assignment questions.
For
Theoretical Answer |
|
For
Numerical Answer |
||
Assessment Parameter |
Weightage |
Assessment Parameter |
Weightage |
|
Introduction |
20% |
Understanding and usage of the formula |
20% |
|
Concepts and Application related to the
question |
60% |
Procedure / Steps |
50% |
|
Conclusion |
20% |
|
Correct Answer & Interpretation |
30% |
June 2021 Examination
1. Nemi Mehta is owning 50
Hectares of land near Junagadh. On his Farm, he cultivates Giloy, which is a
medicinal plant in Ayurveda. The below-given table shows the sales of ‘Giloy
Vati’ that his team is preparing as per one Ayurveda script (book), and the
amount they spend on the Advertisement of it.
Nemi’s problem is to analyze
the effect of Advertisement on sales. Firstly, He wants to understand the
presence of a linear relationship between the sales and ‘amount spent in advertisement’.
He also wants to run a correlation and regression to know whether he should
keep spending money on Advertisements or not. If sales figures are not affected
by advertisement, he should not spend money on it.
So, take the EXCEL output of
the following and write the interpretation.
- Appropriate
type of Graph which can exhibit the linear relation b/w variables.
- Karl
Pearson’s Correlation Coefficient
- Regression
Analysis
- Graph
that shows predicted v/s actual sales figures.
Region
code |
Sales (INR 000s) |
Advertising (TV spots per month) (in INR,
000s) |
1 |
260.3 |
5 |
2 |
286.1 |
7 |
3 |
279.4 |
6 |
4 |
410.8 |
9 |
5 |
438.2 |
12 |
6 |
315.3 |
8 |
7 |
565.1 |
11 |
8 |
570.0 |
16 |
9 |
426.1 |
13 |
10 |
315.0 |
7 |
11 |
403.6 |
10 |
12 |
220.5 |
4 |
13 |
343.6 |
9 |
14 |
644.6 |
17 |
15 |
520.4 |
19 |
16 |
329.5 |
9 |
17 |
426.0 |
11 |
18 |
343.2 |
8 |
19 |
450.4 |
13 |
20 |
421.8 |
14 |
Answer 1
Nemi
Mehta is having 50 hectares of land near the Junagadh, she is growing the Giloy
and making the GiloyVati from the medicines, she is also spending amount on the
advertisement and she is eager to interest to know that is the advertisement is
having any correlation with the sales or not. This means is there any positive
or negative correlation is having on the sales of the
2. The table
given below is the ‘single year age population’ (taken from census 2011). This
table shows the population of people (age-wise) living in Leh at the time of
the census 2011 survey. Transform this ungrouped data into Grouped data by
forming age groups (only five age groups), and then find out Mean, Variance,
Standard deviation, Ogive, and Histogram. Write the summary based on your
calculations.
Age in Yea
rs |
Populati
on |
Age in Yea
rs |
Populati
on |
Age in Yea
rs |
Populati
on |
Age in Yea
rs |
Populati
on |
Age in Yea
rs |
Populati
on |
|
|
11 |
1998 |
22 |
2839 |
33 |
2696 |
44 |
1652 |
1 |
1958 |
12 |
1916 |
23 |
2935 |
34 |
2781 |
45 |
1806 |
2 |
1725 |
13 |
2138 |
24 |
3601 |
35 |
2799 |
46 |
1460 |
3 |
1814 |
14 |
2139 |
25 |
4110 |
36 |
2450 |
47 |
1226 |
4 |
1768 |
15 |
2096 |
26 |
4089 |
37 |
2142 |
48 |
1225 |
5 |
1871 |
16 |
2044 |
27 |
3716 |
38 |
2114 |
49 |
1006 |
6 |
1888 |
17 |
2027 |
28 |
3702 |
39 |
1725 |
50 |
1454 |
7 |
1768 |
18 |
2065 |
29 |
3084 |
40 |
2218 |
|
|
8 |
1712 |
19 |
2013 |
30 |
3475 |
41 |
1802 |
|
|
9 |
1780 |
20 |
2459 |
31 |
2844 |
42 |
1751 |
|
|
10 |
1862 |
21 |
2594 |
32 |
2684 |
43 |
1659 |
|
|
Source: Data.Gov.in
Answer 2.
The
table given below is as follows for the single year age population that has
been taken from census 2011, the table which has been taken age-wise is as
follows.
3.a. The given
table shows the rainfall of Gujarat Region. Forecast the rainfall using Exponential
Smoothing. Use Alpha =0.2, 0.5 and 0.8. Data is available from 1997 to 2016,
use this series for the calculation and forecast the rainfall for the year
2017. To know, what extent the prediction is correct, actual rainfall for 2017
(1024.4 millimeters) is provided. Based
on MSE and MAD, find out which alpha
values among the three suggestions are relatively near to actual value?
SUBDIVISION |
YEAR |
ANNUAL (in MM) |
Gujarat Region |
1997 |
1068.9 |
Gujarat Region |
1998 |
1070 |
Gujarat Region |
1999 |
568.4 |
Gujarat Region |
2000 |
550.6 |
Gujarat Region |
2001 |
849 |
Gujarat Region |
2002 |
637.2 |
Gujarat Region |
2003 |
1160.3 |
Gujarat Region |
2004 |
1005.8 |
Gujarat Region |
2005 |
1316.4 |
Gujarat Region |
2006 |
1478 |
Gujarat Region |
2007 |
1178.9 |
Gujarat Region |
2008 |
911.1 |
Gujarat Region |
2009 |
641.6 |
Gujarat Region |
2010 |
1088.7 |
Gujarat Region |
2011 |
890.5 |
Gujarat Region |
2012 |
714 |
Gujarat Region |
2013 |
1118.6 |
Gujarat Region |
2014 |
705.7 |
Gujarat Region |
2015 |
622.9 |
Gujarat Region |
2016 |
764.9 |
Source: Data.Gov.in
Answer 3 a:
Calculation
of the forecast when the alpha value is 0.20, 0.50, and 0.80 is as follows:
By
using the formula of the exponential smoothing is as follows:
Ft
= α x A t-1)
+ ( 1- α ) X ( F( t-
1) )
3.b. A new gas-electric
hybrid car has recently hit the market. The distance traveled on 1 gallon of
fuel is normally distributed with a mean of 65 miles and a standard deviation
of 4 miles. Find the probability of the following events. (show the concerned
region by z curve)
1. The car travels more
than 70 miles per gallon.
2. The car travels less
than 60 miles per gallon.
3. The car travels between
55 and 70 miles per gallon.
(5 Marks)
Answer 3 b:
The
distance traveled on 1-gallon of fuel is normally distributed with a mean of 65
miles and a standard deviation of 4 miles.
The
Z curve when the car travels more
Dear students, get latest Solved NMIMS assignments and
case study help by professionals.
Mail us at : help.mbaassignments@gmail.com
Call us at : 08263069601
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