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NMIMS Global Access
School for Continuing Education
(NGA-SCE)
Course: Business Statistics
Internal Assignment
Applicable for September 2020 Examination
Assignment Marks: 30
Instructions:
· All Questions carry equal
marks.
· All Questions are compulsory
· All answers to be explained in
not more than 1000 words for question 1 and 2 and for question 3 in not more
than 500 words for each subsection. Use relevant examples, illustrations as far
aspossible.
· All answers to be written
individually. Discussion and group work is not advisable.
· Students are free to refer to
any books/reference material/website/internet for attempting theirassignments,
but are not allowed to copy the matter as it is from the source of reference.
· Students should write the
assignment in their own words. Copying of assignments from otherstudents is not
allowed.
· Students should follow the
following parameter for answering the assignment questions.
For Theoretical Answer |
|
For Numerical Answer |
||
Assessment Parameter |
Weightage |
Assessment Parameter |
Weightage |
|
Introduction |
20% |
Understanding and usage of the formula |
20% |
|
Concepts and Application related to the question |
60% |
Procedure / Steps |
50% |
|
Conclusion |
20% |
|
Correct Answer & Interpretation |
30% |
Question 1: Data Set:
Sample of 7 different species of fish has been taken
and their weight in grams, lengths (vertical, diagonal, cross given as length
1, length 2 and length 3 respectively), height and width in cm is given below:
Species |
Weight |
Length1 |
Length2 |
Length3 |
Height |
Width |
Bream |
725 |
31.8 |
35 |
40.9 |
16.36 |
6.0532 |
Bream |
720 |
32 |
35 |
40.6 |
16.3618 |
6.09 |
Bream |
714 |
32.7 |
36 |
41.5 |
16.517 |
5.8515 |
Bream |
850 |
32.8 |
36 |
41.6 |
16.8896 |
6.1984 |
Bream |
1000 |
33.5 |
37 |
42.6 |
18.957 |
6.603 |
Bream |
920 |
35 |
38.5 |
44.1 |
18.0369 |
6.3063 |
Bream |
955 |
35 |
38.5 |
44 |
18.084 |
6.292 |
Bream |
925 |
36.2 |
39.5 |
45.3 |
18.7542 |
6.7497 |
Bream |
975 |
37.4 |
41 |
45.9 |
18.6354 |
6.7473 |
Bream |
950 |
38 |
41 |
46.5 |
17.6235 |
6.3705 |
Roach |
0 |
19 |
20.5 |
22.8 |
6.4752 |
3.3516 |
Roach |
110 |
19.1 |
20.8 |
23.1 |
6.1677 |
3.3957 |
Roach |
120 |
19.4 |
21 |
23.7 |
6.1146 |
3.2943 |
Roach |
150 |
20.4 |
22 |
24.7 |
5.8045 |
3.7544 |
Roach |
145 |
20.5 |
22 |
24.3 |
6.6339 |
3.5478 |
Roach |
160 |
20.5 |
22.5 |
25.3 |
7.0334 |
3.8203 |
Roach |
140 |
21 |
22.5 |
25 |
6.55 |
3.325 |
Roach |
160 |
21.1 |
22.5 |
25 |
6.4 |
3.8 |
Roach |
169 |
22 |
24 |
27.2 |
7.5344 |
3.8352 |
Roach |
161 |
22 |
23.4 |
26.7 |
6.9153 |
3.6312 |
Roach |
200 |
22.1 |
23.5 |
26.8 |
7.3968 |
4.1272 |
Roach |
180 |
23.6 |
25.2 |
27.9 |
7.0866 |
3.906 |
Roach |
290 |
24 |
26 |
29.2 |
8.8768 |
4.4968 |
Roach |
272 |
25 |
27 |
30.6 |
8.568 |
4.7736 |
Roach |
390 |
29.5 |
31.7 |
35 |
9.485 |
5.355 |
Whitefish |
270 |
23.6 |
26 |
28.7 |
8.3804 |
4.2476 |
Whitefish |
270 |
24.1 |
26.5 |
29.3 |
8.1454 |
4.2485 |
Whitefish |
306 |
25.6 |
28 |
30.8 |
8.778 |
4.6816 |
Whitefish |
540 |
28.5 |
31 |
34 |
10.744 |
6.562 |
Whitefish |
800 |
33.7 |
36.4 |
39.6 |
11.7612 |
6.5736 |
Whitefish |
1000 |
37.3 |
40 |
43.5 |
12.354 |
6.525 |
Parkki |
55 |
13.5 |
14.7 |
16.5 |
6.8475 |
2.3265 |
Parkki |
60 |
14.3 |
15.5 |
17.4 |
6.5772 |
2.3142 |
Parkki |
90 |
16.3 |
17.7 |
19.8 |
7.4052 |
2.673 |
Parkki |
120 |
17.5 |
19 |
21.3 |
8.3922 |
2.9181 |
Parkki |
150 |
18.4 |
20 |
22.4 |
8.8928 |
3.2928 |
Parkki |
140 |
19 |
20.7 |
23.2 |
8.5376 |
3.2944 |
Parkki |
170 |
19 |
20.7 |
23.2 |
9.396 |
3.4104 |
Parkki |
145 |
19.8 |
21.5 |
24.1 |
9.7364 |
3.1571 |
Parkki |
200 |
21.2 |
23 |
25.8 |
10.3458 |
3.6636 |
Parkki |
273 |
23 |
25 |
28 |
11.088 |
4.144 |
Parkki |
300 |
24 |
26 |
29 |
11.368 |
4.234 |
Perch |
5.9 |
7.5 |
8.4 |
8.8 |
2.112 |
1.408 |
Perch |
32 |
12.5 |
13.7 |
14.7 |
3.528 |
1.9992 |
Perch |
40 |
13.8 |
15 |
16 |
3.824 |
2.432 |
Perch |
51.5 |
15 |
16.2 |
17.2 |
4.5924 |
2.6316 |
Perch |
70 |
15.7 |
17.4 |
18.5 |
4.588 |
2.9415 |
Perch |
100 |
16.2 |
18 |
19.2 |
5.2224 |
3.3216 |
Perch |
78 |
16.8 |
18.7 |
19.4 |
5.1992 |
3.1234 |
Perch |
80 |
17.2 |
19 |
20.2 |
5.6358 |
3.0502 |
Perch |
85 |
17.8 |
19.6 |
20.8 |
5.1376 |
3.0368 |
Perch |
85 |
18.2 |
20 |
21 |
5.082 |
2.772 |
Perch |
110 |
19 |
21 |
22.5 |
5.6925 |
3.555 |
Pike |
430 |
35.5 |
38 |
40.5 |
7.29 |
4.5765 |
Pike |
345 |
36 |
38.5 |
41 |
6.396 |
3.977 |
Pike |
456 |
40 |
42.5 |
45.5 |
7.28 |
4.3225 |
Pike |
510 |
40 |
42.5 |
45.5 |
6.825 |
4.459 |
Pike |
540 |
40.1 |
43 |
45.8 |
7.786 |
5.1296 |
Pike |
500 |
42 |
45 |
48 |
6.96 |
4.896 |
Pike |
567 |
43.2 |
46 |
48.7 |
7.792 |
4.87 |
Pike |
770 |
44.8 |
48 |
51.2 |
7.68 |
5.376 |
Pike |
950 |
48.3 |
51.7 |
55.1 |
8.9262 |
6.1712 |
Pike |
1250 |
52 |
56 |
59.7 |
10.6863 |
6.9849 |
Smelt |
6.7 |
9.3 |
9.8 |
10.8 |
1.7388 |
1.0476 |
Smelt |
7.5 |
10 |
10.5 |
11.6 |
1.972 |
1.16 |
Smelt |
7 |
10.1 |
10.6 |
11.6 |
1.7284 |
1.1484 |
Smelt |
9.7 |
10.4 |
11 |
12 |
2.196 |
1.38 |
Smelt |
9.8 |
10.7 |
11.2 |
12.4 |
2.0832 |
1.2772 |
Smelt |
8.7 |
10.8 |
11.3 |
12.6 |
1.9782 |
1.2852 |
Smelt |
10 |
11.3 |
11.8 |
13.1 |
2.2139 |
1.2838 |
Smelt |
9.9 |
11.3 |
11.8 |
13.1 |
2.2139 |
1.1659 |
Smelt |
9.8 |
11.4 |
12 |
13.2 |
2.2044 |
1.1484 |
Smelt |
12.2 |
11.5 |
12.2 |
13.4 |
2.0904 |
1.3936 |
Q1: Find the mean and standard
deviation for each type of fish for every variable.
Answer: 1. To compute the mean and standard deviation we will use the below formulas.
The mean is computed as follows,
Also, the sample variance is,
Question 2. If you need to choose a
fish on the basis of weight, which fish you choose?
Answer : The mean and
standard deviation for Weight variable for all species is below:
Species |
Mean |
Standard
Deviation |
Bream |
873.4 |
113.1471019 |
Roach |
176.4666667 |
88.95574073 |
Whitefish |
531 |
309.6029716 |
Parkki |
154.8181818 |
78.75508642 |
Question.3. Find mean, median,
quartiles for the entire data set for each variable. (10 marks)
Answer : Mean:
By using the same formula as in part (a), the
mean are,
The sample size is n = 73. The provided sample data along with the data required to compute the sample mean for each variable of all species is shown in the table below:
Mean |
Question 2 : Regress the following:
(10 Marks)
- Taking
weight as dependent variable and height as independent variable. Is
variable is found to be significant?
Regression Statistics |
||||||
Multiple
R |
0.094799718 |
|||||
|
- Taking
weight as dependent variable and width as independent variable. Is
variable is found to be significant?
Answer :
Regression Statistics |
||||||
Multiple R |
0.913804714 |
|||||
R Square |
0.835039055 |
- Taking
weight as dependent variable and length1, length 2 and length 3 as
independent variable. Are variables is found to be significant? Which
variable is not significant?
Answer :
Regression Statistics |
||||||
Multiple
R |
0.938718572 |
|||||
R
Square |
0.881192557 |
|||||
Adjusted
R Square |
0.876027017 |
- Taking
weight as dependent variable and height, width, length 1, length 2 and
length 3 as independent variable.
Answer :
Regression Statistics |
||||||
Multiple
R |
0.940567787 |
|||||
R
Square |
0.884667763 |
|||||
Adjusted
R Square |
0.876060879 |
|||||
Standard
Error |
117.7864532 |
|||||
Observations |
73 |
|||||
ANOVA |
||||||
|
df |
SS |
MS |
F |
Significance F |
|
Regression |
5 |
7130089.418 |
1426017.884 |
102.7860752 |
4.85005E-30 |
|
|
- On
basis of adjusted R square compare the model of part a, b, c and d. which
model is best to predict weight?
Models |
Adjusted R Square |
a)
Weight vs Height |
-0.004970943 |
b)
Weight vs Width |
0.832715661 |
Question 3. The
daily COVID 19 cases (in hundred) for Delhi for past 2 week is summarize in the
following table:
Day |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
11 |
12 |
13 |
14 |
Cases |
28 |
29 |
33 |
31 |
37 |
34 |
36 |
43 |
41 |
32 |
34 |
37 |
39 |
32 |
- Using exponential smoothing method forecast the
cases for 15 days, taking alpha as 0.3 and Initial forecast is the average
of all data. (5 Marks)
Answer : First we need to compute mean of the data.
The mean is computed as follows,
Mean = (1/14)* 486 = 34.7142857.
- Using linear trend analysis, find the trend line
for number of COVID 19 cases in Delhi and forecast for next 3 days. Also
compute the Mean Square Error. (5 Marks)
Answer : The independent variable is Time, and the dependent variable is Cases. In order to compute the regression coefficients, the following table needs to be used:
Days (X) |
Cases (Y) |
Days*Cases (XY) |
Days^2 (X^2) |
Cases^2 (Y^2) |
|
1 |
28 |
28 |
1 |
784 |
|
2 |
29 |
58 |
4 |
841 |
|
3 |
33 |
99 |
9 |
1089 |
|
4 |
31 |
124 |
16 |
961 |
|
5 |
37 |
185 |
25 |
1369 |
|
6 |
34 |
204 |
36 |
1156 |
|
7 |
36 |
252 |
49 |
1296 |
|
8 |
43 |
344 |
64 |
1849 |
|
9 |
41 |
369 |
81 |
1681 |
|
10 |
32 |
320 |
100 |
1024 |
|
11 |
34 |
374 |
121 |
1156 |
|
12 |
37 |
444 |
144 |
1369 |
|
13 |
39 |
507 |
169 |
1521 |
|
14 |
32 |
448 |
196 |
1024 |
|
Sum = |
105 |
486 |
3756 |
1015 |
17120 |
Hello MBA aspirants,
Get MBA assignments of NMIMS University solved by
educational professionals at a nominal charge.
Mail us at: help.mbaassignments@gmail.com
Call us at: 08263069601
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