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Spring 2015 ASSIGNMENT
PROGRAM
|
BSc
IT
|
SEMESTER
|
SECOND
|
SUBJECT
CODE & NAME
|
BT0069,
Discrete Mathematics
|
CREDIT
|
4
|
BK
ID
|
B0953
|
MAX.MARKS
|
60
|
Q.1 If U = {a,b,c,d,e}, A ={a,c,d}, B = {d,e}, C =
{b,c,e}
Evaluate the following:
(a) A’ ´ (B-C)
(b)(AÈB)’´(BÇC)
(c)(A-B)´(B-C)
(d)(BÈC)’´A
(e)(B-A)´C’
Answer:
(a) A’
´ (B-C)
A’ =
set of those elements which belong to U but not to A.
A’ =
(b, e)
(B-C)
= (d)
A’ ´ (B-C) = (b,e)´(d)
2 (i) State the principle of inclusion and exclusion.
Answer:
I)
Principle
of Inclusion and Exclusion
For any two sets P and Q, we have;
i) |P ﮟ Q| ≤ |P| + |Q| where |P| is
the number of elements in P, and |Q| is the number elements in Q.
3 If G is a group, then
i) The identity element of G is unique.
ii) Every element in G has unique inverse in G.
iii)
For any a єG,
we have (a-1)-1 = a.
|
iv) For all a, b є G, we have (a.b)-1 = b-1.a-1. 4x 2.5 10
Answer: i)
Let e, f be two identity elements in G.
Since e is the identity, we have e.f= f.
Since f is the identity, we have e.f = e.
Therefore, e = e.f = f.
Hence the identity element is unique.
ii)Let a be in G and a1, a2
4 (i) Define valid argument
Answer: i)Definition
Any conclusion, which is arrived at by
following the rules is called a valid conclusion and argument is called a valid
argument.5 (i) Construct a grammar for
the language.
'L⁼{x/ xє{ ab} the number
of as in x is a multiple of 3.
|
Answer: i)
Let T = {a, b} and N = {S, A, B},
S is a starting symbol.
The set of productions: F
S
|
®
|
bS
|
S
|
®
|
b
|
S
|
®
|
aA
|
6 (i) Define tree with example
Answer: i)
Definition
A connected graph without circuits is
called a tree.
Example
Consider the two trees G1 = (V, E1) and
G2 = (V,
E2) where V = {a, b, c, d, e, f, g, h, i, j}
E1 =
{{a, c}, {b, c}, {c, d}, {c, e}, {e, g}, {f, g}, {g, i}, {h, i}, {i, j}} E2 = {(c, a),
(c, b), (c, d), (c, f), (f, e), (f, i), (g, d), (h, e), (j, g)}
Dear
students get fully solved assignments
Send
your semester & Specialization name to our mail id :
“
help.mbaassignments@gmail.com ”
or
Call
us at : 08263069601
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