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DRIVE
|
SUMMER 2015
|
PROGRAM
|
MBA
|
SEMESTER
|
1
|
SUBJECT CODE & NAME
|
MB0040 STATISTICS FOR MANAGEMENT
|
BK ID
|
B1731
|
CREDIT & MARKS
|
4 Credits, 60 marks
|
Name
|
XXXXX
|
Send
your semester & Specialization name to our mail id :
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ASSIGNMENT
Q1 Distinguish between
Classification and Tabulation. Explain the structure and components of a Table
with an example.
·
Meaning of Classification and Tabulation
·
Differences between Classification and Tabulation
·
Structure and Components of a Table with an example
Answer.
Meaning of Classification and
Tabulation
Classification
According to Secrist, “Classification is the
process of arranging data into sequences and groups according to their common
characteristics or separating them into different but related parts”. According
to Stockton and Clark, “The process of grouping large number of individual
facts and observations, on the basis of similarity
Q2. (a) Explain Arithmetic mean. 3
(b) The mean wage is Rs. 75 per
day, SD wage is Rs. 5 per day for a group of 1000 workers and the same is Rs.
60 and Rs. 4.5 for the other group of 1500 workers. Find the mean and standard
deviation for the entire group. 7
Answer:
(a)
Arithmetic mean: Arithmetic
mean is defined as the sum of all values divided by number of values and
is represented by X . Arithmetic mean is also called ‘average’. It is most commonly
used measures of central tendency. Arithmetic Mean of a series is the value
obtained by adding all the observations of a series and
Q3.
Mr. Arun and Mr. Bhandari play a game. If Mr. Arun picks up an even number from
1 to 6, Mr. Bhandari will pay him double the amount equal to picked up number.
If Mr. Arun picks up an odd number then he has to pay amount equal to double
the picked up number. What is Mr. Arun’s expectation? 10
Solution: Let Xi be
the random variable and P(Xi) be its probability. The probabilities are
indicated in table.
Required
Values for Calculating Mean and Variance for the Data
NO.
|
(Xi)
|
P(Xi)
|
Xi P(Xi)
|
1
|
-2
|
1/6
|
- 2/6
|
2
|
4
|
1/6
|
4/6
|
Q4. The probability that an
employee will get an occupational disease is 20%. In a firm having five
employees, what is the probability that:
i) None of the employees get the
disease 4
ii) Exactly two will get the
disease 3
iii) More than four will contract
the disease 3
Answer:
Solution
Given that:
p 20/100
0.2
Q5. Microsoft estimated that out
of 10,000 potential software buyers, 35% wait to purchase the new OS Windows
Vista, until an upgrade has been released. After an advertising campaign to
reassure the public was released, Microsoft surveyed 3000 buyers and found 950
who are still skeptical. At 5% level of significance, can the company conclude
that the population of skeptical people had decreased? 10
Answer:
Solution:
The procedure is explained in the following
steps:
1. Null hypothesis Ho: p = .35
Q6. Explain Chi-square test and
the conditions for applying chi-square test. (Meaning, Conditions) 5, 5
Answer:
Chi-Square test: The
Chi-square test is one of the most commonly used non-parametric tests in
statistical work. The Greek Letter 2 is used to denote this test. 2 describe
the magnitude of discrepancy between the observed and the expected frequencies.
The value of 2 is calculated as:
Where, O1, O2, O3….On are the observed
frequencies and E1, E2, E3…En are the corresponding expected or theoretical
frequencies.
Dear
students get fully solved assignments
Send
your semester & Specialization name to our mail id :
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